Xuan spent $26 on some oranges, lemons and pomegranates in the ratio of 6 : 3 : 4. The number of oranges was
35 the number of lemons. The ratio of the number of pomegranates to the number of lemons was 3 : 1. The oranges were sold at 2 for a dollar.
- How many fruits did she buy altogether?
- How much did each lemon cost?
Amount spent |
Oranges |
Lemons |
Pomegranates |
Total |
6 u |
3 u |
4 u |
13 u |
Total amount spent on fruits
= 6 u + 3 u + 4 u
= 13 u
13 u = 26
1 u = 26 ÷ 13 = 2
Amount that Xuan spent on oranges
= 6 u
= 6 x 2
= $12
Total number of oranges that Xuan bought
= 12 x 2
= 24
Number of fruits bought |
Oranges |
Lemons |
Pomegranates |
3x1 |
5x1 |
|
|
1x5 |
3x5 |
3 p |
5 p |
15 p |
The number of lemons bought is repeated. Make the number of lemons the same. LCM of 1 and 5 is 5.
3 p = 24
1 p = 24 ÷ 3 = 8
Total number of fruits that Xuan bought
= 3 p + 5 p + 15 p
= 23 p
= 23 x 8
= 184
(b)
Total number of lemons that Xuan bought
= 5 p
= 5 x 8
= 40
Total amount that Xuan paid for the lemons
= 3 u
= 3 x 2
= $6
Price of each lemon
= 6 ÷ 40
= $0.15
Answer(s): (a) 184; (b) $0.15