Jane spent $110 on some mangoes, pomegranates and lemons in the ratio of 2 : 4 : 5. The number of mangoes was
12 the number of pomegranates. The ratio of the number of lemons to the number of pomegranates was 6 : 5. The mangoes were sold at 4 for a dollar.
- How many fruits did she buy altogether?
- How much did each pomegranate cost?
Amount spent |
Mangoes |
Pomegranates |
Lemons |
Total |
2 u |
4 u |
5 u |
11 u |
Total amount spent on fruits
= 2 u + 4 u + 5 u
= 11 u
11 u = 110
1 u = 110 ÷ 11 = 10
Amount that Jane spent on mangoes
= 2 u
= 2 x 10
= $20
Total number of mangoes that Jane bought
= 20 x 4
= 80
Number of fruits bought |
Mangoes |
Pomegranates |
Lemons |
1x5 |
2x5 |
|
|
5x2 |
6x2 |
5 p |
10 p |
12 p |
The number of pomegranates bought is repeated. Make the number of pomegranates the same. LCM of 5 and 2 is 10.
5 p = 80
1 p = 80 ÷ 5 = 16
Total number of fruits that Jane bought
= 5 p + 10 p + 12 p
= 27 p
= 27 x 16
= 432
(b)
Total number of pomegranates that Jane bought
= 10 p
= 10 x 16
= 160
Total amount that Jane paid for the pomegranates
= 4 u
= 4 x 10
= $40
Price of each pomegranate
= 40 ÷ 160
= $0.25
Answer(s): (a) 432; (b) $0.25