Min spent $48 on some apples, pears and pomegranates in the ratio of 2 : 3 : 1. The number of apples was ¹₂ the number of pears. The ratio of the number of pomegranates to the number of pears was 4 : 3. The apples were sold at 3 for a dollar.

1. How many fruits did she buy altogether?
2. How much did each pear cost?

Amount spent
Apples	Pears	Pomegranates	Total
2 u	3 u	1 u	6 u

Total amount spent on fruits
= 2 u + 3 u + 1 u
= 6 u

6 u = 48

1 u = 48 ÷ 6 = 8

Amount that Min spent on apples
= 2 u
= 2 x 8
= $16 

Total number of apples that Min bought
= 16 x 3
= 48

Number of fruits bought
Apples	Pears	Pomegranates
1x3	2x3
	3x2	4x2
3 p	6 p	8 p

The number of pears bought is repeated.  Make the number of pears the same.  LCM of 3 and 2 is 6.

3 p = 48

1 p = 48 ÷ 3 = 16

Total number of fruits that Min bought
= 3 p + 6 p + 8 p
= 17 p
= 17 x 16
= 272

(b)
Total number of pears that Min bought
= 6 p
= 6 x 16
= 96

Total amount that Min paid for the pears
= 3 u
= 3 x 8
= $24

Price of each pear
= 24 ÷ 96
= $0.25 

Answer(s): (a) 272; (b) $0.25