Cody, Ian, Riordan and George paid a total of $462 for a present. George paid
59 of what the rest paid. Cody paid 20% of what the rest paid. Ian and Riordan paid an equal amount of money. How much did Riordan pay?
Cody |
Ian |
Riordan |
George |
Total |
9x3 |
5x3 |
14x3 |
1x7 |
5x7 |
6x7 |
|
1 |
1 |
|
|
7 u |
10 u |
10 u |
15 u |
42 u |
20%=
20100=
15 Cody's share : Total share = 1 : 5
The total amount paid for the present is repeated. Make the total amount the same. LCM of 14 and 6 is 42.
Amount that Ian, Riordan and George paid = 35 u
Amount that Ian and Riordan paid
= 35 u - 15 u
= 20 u
The amount that Ian and Riordan each paid is the same.
Amount that Ian and Riordan each paid
= 20 u ÷ 2
= 10 u
Cost of the present = 42 u
42 u = 462
1 u = 462 ÷ 42 = 11
Amount that Riordan paid
= 10 u
= 10 x 11
= $110
Answer(s): $110