Riordan, Cole, Wesley and Fabian paid a total of $72 for a present. Fabian paid
27 of what the rest paid. Riordan paid 50% of what the rest paid. Cole and Wesley paid an equal amount of money. How much did Wesley pay?
| Riordan |
Cole |
Wesley |
Fabian |
Total |
| 7x1 |
2x1 |
9x1 |
| 1x3 |
2x3 |
3x3 |
| |
1 |
1 |
|
|
| 3 u |
2 u |
2 u |
2 u |
9 u |
50%=
50100=
12 Riordan's share : Total share = 1 : 2
The total amount paid for the present is repeated. Make the total amount the same. LCM of 9 and 3 is 9.
Amount that Cole, Wesley and Fabian paid = 6 u
Amount that Cole and Wesley paid
= 6 u - 2 u
= 4 u
The amount that Cole and Wesley each paid is the same.
Amount that Cole and Wesley each paid
= 4 u ÷ 2
= 2 u
Cost of the present = 9 u
9 u = 72
1 u = 72 ÷ 9 = 8
Amount that Wesley paid
= 2 u
= 2 x 8
= $16
Answer(s): $16
