Ahmad, Bobby, Simon and Xavier paid a total of $210 for a present. Xavier paid ¹₄ of what the rest paid. Ahmad paid 40% of what the rest paid. Bobby and Simon paid an equal amount of money. How much did Simon pay?

Ahmad	Bobby	Simon	Xavier	Total
4x7			1x7	5x7
2x5	5x5			7x5
	1	1
10 u	9 u	9 u	7 u	35 u

40%= ⁴⁰₁₀₀= ²₅
Ahmad's share : Total share = 2 : 5

The total amount paid for the present is repeated.  Make the total amount the same.  LCM of 5 and 7 is 35.

Amount that Bobby, Simon and Xavier paid = 25 u

Amount that Bobby and Simon paid
= 25 u - 7 u
= 18 u

The amount that Bobby and Simon each paid is the same.

Amount that Bobby and Simon each paid
= 18 u ÷ 2
= 9 u

Cost of the present = 35 u

35 u = 210

1 u = 210 ÷ 35 = 6

Amount that Simon paid
= 9 u
= 9 x 6
= $54

Answer(s): $54