Paul, Riordan, Lee and Charlie paid a total of $81 for a present. Charlie paid
45 of what the rest paid. Paul paid 50% of what the rest paid. Riordan and Lee paid an equal amount of money. How much did Lee pay?
| Paul |
Riordan |
Lee |
Charlie |
Total |
| 5x1 |
4x1 |
9x1 |
| 1x3 |
2x3 |
3x3 |
| |
1 |
1 |
|
|
| 3 u |
1 u |
1 u |
4 u |
9 u |
50%=
50100=
12 Paul's share : Total share = 1 : 2
The total amount paid for the present is repeated. Make the total amount the same. LCM of 9 and 3 is 9.
Amount that Riordan, Lee and Charlie paid = 6 u
Amount that Riordan and Lee paid
= 6 u - 4 u
= 2 u
The amount that Riordan and Lee each paid is the same.
Amount that Riordan and Lee each paid
= 2 u ÷ 2
= 1 u
Cost of the present = 9 u
9 u = 81
1 u = 81 ÷ 9 = 9
Amount that Lee paid
= 1 u
= 1 x 9
= $9
Answer(s): $9
