Tom, Luis, Ahmad and Luke paid a total of $60 for a present. Luke paid
37 of what the rest paid. Tom paid 20% of what the rest paid. Luis and Ahmad paid an equal amount of money. How much did Ahmad pay?
| Tom |
Luis |
Ahmad |
Luke |
Total |
| 7x3 |
3x3 |
10x3 |
| 1x5 |
5x5 |
6x5 |
| |
1 |
1 |
|
|
| 5 u |
8 u |
8 u |
9 u |
30 u |
20%=
20100=
15 Tom's share : Total share = 1 : 5
The total amount paid for the present is repeated. Make the total amount the same. LCM of 10 and 6 is 30.
Amount that Luis, Ahmad and Luke paid = 25 u
Amount that Luis and Ahmad paid
= 25 u - 9 u
= 16 u
The amount that Luis and Ahmad each paid is the same.
Amount that Luis and Ahmad each paid
= 16 u ÷ 2
= 8 u
Cost of the present = 30 u
30 u = 60
1 u = 60 ÷ 30 = 2
Amount that Ahmad paid
= 8 u
= 8 x 2
= $16
Answer(s): $16
