Seth, Jenson, Ken and Lee paid a total of $132 for a present. Lee paid
47 of what the rest paid. Seth paid 50% of what the rest paid. Jenson and Ken paid an equal amount of money. How much did Ken pay?
| Seth |
Jenson |
Ken |
Lee |
Total |
| 7x3 |
4x3 |
11x3 |
| 1x11 |
2x11 |
3x11 |
| |
1 |
1 |
|
|
| 11 u |
5 u |
5 u |
12 u |
33 u |
50%=
50100=
12 Seth's share : Total share = 1 : 2
The total amount paid for the present is repeated. Make the total amount the same. LCM of 11 and 3 is 33.
Amount that Jenson, Ken and Lee paid = 22 u
Amount that Jenson and Ken paid
= 22 u - 12 u
= 10 u
The amount that Jenson and Ken each paid is the same.
Amount that Jenson and Ken each paid
= 10 u ÷ 2
= 5 u
Cost of the present = 33 u
33 u = 132
1 u = 132 ÷ 33 = 4
Amount that Ken paid
= 5 u
= 5 x 4
= $20
Answer(s): $20
