Four boys, Daniel, Gabriel, Ryan and Xavier saved some money. Gabriel's savings was
23 of the total savings of Daniel, Ryan and Xavier. Daniel's savings was 10% of the total savings. Ryan's savings was
27 of the total savings of Gabriel and Xavier. If Gabriel's savings was $108, how much less was Daniel's savings than the total of the other three boys?
| Gabriel |
Xavier |
Ryan |
Daniel |
Total |
| 2x2 |
3x2 |
5x2 |
| 9x1 |
1x1 |
10x1 |
| 7x1 |
2x1 |
|
|
| 4 u |
3 u |
2 u |
1 u |
10 u |
10% →
10100=
110 Daniel's savings : Total savings = 1 : 10
Gabriel's savings = 4 u
4 u = 108
1 u = 108 ÷ 4 = 27
Daniel's savings = 1 u
Savings of the other three boys
= 4 u + 3 u + 2 u
= 9 u
Savings that Daniel had less than the total of the three other boys
= 9 u - 1 u
= 8 u
= 8 x 27
= $216
Answer(s): $216
