Four boys, Gabriel, Peter, Xavier and Perry saved some money. Peter's savings was
12 of the total savings of Gabriel, Xavier and Perry. Gabriel's savings was 10% of the total savings. Xavier's savings was
27 of the total savings of Peter and Perry. If Peter's savings was $190, how much less was Xavier's savings than the total of the other three boys?
| Peter |
Perry |
Xavier |
Gabriel |
Total |
| 1x10 |
2x10 |
3x10 |
| 9x3 |
1x3 |
10x3 |
| 7x3 |
2x3 |
|
|
| 10 u |
11 u |
6 u |
3 u |
30 u |
10% →
10100=
110 Gabriel's savings : Total savings = 1 : 10
Peter's savings = 10 u
10 u = 190
1 u = 190 ÷ 10 = 19
Xavier's savings = 6 u
Savings of the other three boys
= 10 u + 11 u + 3 u
= 24 u
Savings that Xavier had less than the total of the three other boys
= 24 u - 6 u
= 18 u
= 18 x 19
= $342
Answer(s): $342
