Four boys, Ken, Jeremy, Tommy and Gabriel saved some money. Jeremy's savings was
29 of the total savings of Ken, Tommy and Gabriel. Ken's savings was 10% of the total savings. Tommy's savings was
45 of the total savings of Jeremy and Gabriel. If Jeremy's savings was $440, how much less was Ken's savings than the total of the other three boys?
Jeremy |
Gabriel |
Tommy |
Ken |
Total |
2x10 |
9x10 |
11x10 |
9x11 |
1x11 |
10x11 |
5x11 |
4x11 |
|
|
20 u |
35 u |
44 u |
11 u |
110 u |
10% →
10100=
110 Ken's savings : Total savings = 1 : 10
Jeremy's savings = 20 u
20 u = 440
1 u = 440 ÷ 20 = 22
Ken's savings = 11 u
Savings of the other three boys
= 20 u + 35 u + 44 u
= 99 u
Savings that Ken had less than the total of the three other boys
= 99 u - 11 u
= 88 u
= 88 x 22
= $1936
Answer(s): $1936