Four boys, Xavier, Carl, Oscar and Dylan saved some money. Carl's savings was
18 of the total savings of Xavier, Oscar and Dylan. Xavier's savings was 25% of the total savings. Oscar's savings was
12 of the total savings of Carl and Dylan. If Carl's savings was $48, how much less was Xavier's savings than the total of the other three boys?
Carl |
Dylan |
Oscar |
Xavier |
Total |
1x4 |
8x4 |
9x4 |
3x9 |
1x9 |
4x9 |
2x9 |
1x9 |
|
|
4 u |
14 u |
9 u |
9 u |
36 u |
25% →
25100=
14 Xavier's savings : Total savings = 1 : 4
Carl's savings = 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Xavier's savings = 9 u
Savings of the other three boys
= 4 u + 14 u + 9 u
= 27 u
Savings that Xavier had less than the total of the three other boys
= 27 u - 9 u
= 18 u
= 18 x 12
= $216
Answer(s): $216