Four boys, Michael, Howard, Gabriel and Pierre saved some money. Howard's savings was
12 of the total savings of Michael, Gabriel and Pierre. Michael's savings was 20% of the total savings. Gabriel's savings was
13 of the total savings of Howard and Pierre. If Howard's savings was $100, how much less was Gabriel's savings than the total of the other three boys?
| Howard |
Pierre |
Gabriel |
Michael |
Total |
| 1x5 |
2x5 |
3x5 |
| 4x3 |
1x3 |
5x3 |
| 3x3 |
1x3 |
|
|
| 5 u |
4 u |
3 u |
3 u |
15 u |
20% →
20100=
15 Michael's savings : Total savings = 1 : 5
Howard's savings = 5 u
5 u = 100
1 u = 100 ÷ 5 = 20
Gabriel's savings = 3 u
Savings of the other three boys
= 5 u + 4 u + 3 u
= 12 u
Savings that Gabriel had less than the total of the three other boys
= 12 u - 3 u
= 9 u
= 9 x 20
= $180
Answer(s): $180
