Four boys, Tommy, Ian, Gabriel and Asher saved some money. Ian's savings was
45 of the total savings of Tommy, Gabriel and Asher. Tommy's savings was 10% of the total savings. Gabriel's savings was
45 of the total savings of Ian and Asher. If Ian's savings was $1560, how much less was Gabriel's savings than the total of the other three boys?
Ian |
Asher |
Gabriel |
Tommy |
Total |
4x10 |
5x10 |
9x10 |
9x9 |
1x9 |
10x9 |
5x9 |
4x9 |
|
|
40 u |
5 u |
36 u |
9 u |
90 u |
10% →
10100=
110 Tommy's savings : Total savings = 1 : 10
Ian's savings = 40 u
40 u = 1560
1 u = 1560 ÷ 40 = 39
Gabriel's savings = 36 u
Savings of the other three boys
= 40 u + 5 u + 9 u
= 54 u
Savings that Gabriel had less than the total of the three other boys
= 54 u - 36 u
= 18 u
= 18 x 39
= $702
Answer(s): $702