Four boys, Howard, Lee, Jeremy and Cody saved some money. Lee's savings was
23 of the total savings of Howard, Jeremy and Cody. Howard's savings was 10% of the total savings. Jeremy's savings was
45 of the total savings of Lee and Cody. If Lee's savings was $136, how much less was Howard's savings than the total of the other three boys?
Lee |
Cody |
Jeremy |
Howard |
Total |
2x2 |
3x2 |
5x2 |
9x1 |
1x1 |
10x1 |
5x1 |
4x1 |
|
|
4 u |
1 u |
4 u |
1 u |
10 u |
10% →
10100=
110 Howard's savings : Total savings = 1 : 10
Lee's savings = 4 u
4 u = 136
1 u = 136 ÷ 4 = 34
Howard's savings = 1 u
Savings of the other three boys
= 4 u + 1 u + 4 u
= 9 u
Savings that Howard had less than the total of the three other boys
= 9 u - 1 u
= 8 u
= 8 x 34
= $272
Answer(s): $272