Four boys, Dylan, Pierre, Ahmad and Warren saved some money. Pierre's savings was
58 of the total savings of Dylan, Ahmad and Warren. Dylan's savings was 20% of the total savings. Ahmad's savings was
13 of the total savings of Pierre and Warren. If Pierre's savings was $475, how much less was Ahmad's savings than the total of the other three boys?
Pierre |
Warren |
Ahmad |
Dylan |
Total |
5x5 |
8x5 |
13x5 |
4x13 |
1x13 |
5x13 |
3x13 |
1x13 |
|
|
25 u |
14 u |
13 u |
13 u |
65 u |
20% →
20100=
15 Dylan's savings : Total savings = 1 : 5
Pierre's savings = 25 u
25 u = 475
1 u = 475 ÷ 25 = 19
Ahmad's savings = 13 u
Savings of the other three boys
= 25 u + 14 u + 13 u
= 52 u
Savings that Ahmad had less than the total of the three other boys
= 52 u - 13 u
= 39 u
= 39 x 19
= $741
Answer(s): $741