Four boys, Michael, Luis, Tommy and Luke saved some money. Luis's savings was
23 of the total savings of Michael, Tommy and Luke. Michael's savings was 10% of the total savings. Tommy's savings was
45 of the total savings of Luis and Luke. If Luis's savings was $48, how much less was Michael's savings than the total of the other three boys?
Luis |
Luke |
Tommy |
Michael |
Total |
2x2 |
3x2 |
5x2 |
9x1 |
1x1 |
10x1 |
5x1 |
4x1 |
|
|
4 u |
1 u |
4 u |
1 u |
10 u |
10% →
10100=
110 Michael's savings : Total savings = 1 : 10
Luis's savings = 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Michael's savings = 1 u
Savings of the other three boys
= 4 u + 1 u + 4 u
= 9 u
Savings that Michael had less than the total of the three other boys
= 9 u - 1 u
= 8 u
= 8 x 12
= $96
Answer(s): $96