Fiona, Jane, Yen and Kylie went to buy a present for their grandmother. They shared the cost equally among themselves. However, Kylie forgot to bring her money. So, the other 3 girls paid for the present first. Yen paid
511 of the amount Fiona and Jane paid. Jane paid $9 more than Fiona. The next day, Kylie returned $17 to Yen and some money to Fiona and Jane. How much did Kylie return to
- Fiona?
- Jane?
|
Fiona |
Jane |
Yen |
Kylie |
Total |
Comparing the amounts 3 girls paid first |
11 u
|
5 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 9
|
|
|
|
Amounts that each girl paid for Kylie first |
- ? |
- ? |
- 17
|
+ 17 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Yen paid
= 5 u - 4 u
= 1 u
1 u = 17
Total amount that Fiona and Jane paid at first
= 11 u
= 11 x 17
= $187
1 p + 1 p + 9 = 187
2 p = 187 - 9
2 p = 178
1 p = 178 ÷ 2 = 89
Amount that Kylie needed to pay Fiona
= 1 p - 4 u
= 89 - 4 x 17
= 89 - 68
= $21
(b)
Amount that Kylie needed to pay Jane
= (1 p + 9) - 4 u
= (89 + 9) - 4 x 17
= 98 - 68
= $30
Answer(s): (a) $21; (b) $30