Shiyun, Penelope, Kylie and Opal went to buy a souvenir for their father. They shared the cost equally among themselves. However, Opal forgot to bring her money. So, the other 3 girls paid for the souvenir first. Kylie paid
35 of the amount Shiyun and Penelope paid. Penelope paid $13 more than Shiyun. The next day, Opal returned $15 to Kylie and some money to Shiyun and Penelope. How much did Opal return to
- Shiyun?
- Penelope?
|
Shiyun |
Penelope |
Kylie |
Opal |
Total |
Comparing the amounts 3 girls paid first |
5 u
|
3 u
|
|
8 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 13
|
|
|
|
Amounts that each girl paid for Opal first |
- ? |
- ? |
- 15
|
+ 15 + ? |
|
Comparing the amounts each girl should pay |
1x2 = 2 u |
1x2 = 2 u |
1x2 = 2 u |
1x2 = 2 u |
4x2 = 8 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 8 is 8.
Extra amount that Kylie paid
= 3 u - 2 u
= 1 u
1 u = 15
Total amount that Shiyun and Penelope paid at first
= 5 u
= 5 x 15
= $75
1 p + 1 p + 13 = 75
2 p = 75 - 13
2 p = 62
1 p = 62 ÷ 2 = 31
Amount that Opal needed to pay Shiyun
= 1 p - 2 u
= 31 - 2 x 15
= 31 - 30
= $1
(b)
Amount that Opal needed to pay Penelope
= (1 p + 13) - 2 u
= (31 + 13) - 2 x 15
= 44 - 30
= $14
Answer(s): (a) $1; (b) $14