Abi, Zara, Hazel and Marion went to buy a present for their mother. They shared the cost equally among themselves. However, Marion forgot to bring her money. So, the other 3 girls paid for the present first. Hazel paid ⁵₁₁ of the amount Abi and Zara paid. Zara paid $15 more than Abi. The next day, Marion returned $17 to Hazel and some money to Abi and Zara. How much did Marion return to

1. Abi?
2. Zara?

	Abi	Zara	Hazel	Marion	Total
Comparing the amounts 3 girls paid first	11 u		5 u		16 u
Comparing the amounts 2 girls paid first	1 p	1 p + 15
Amounts that each girl paid for Marion first	- ?	- ?	- 17	+ 17 + ?
Comparing the amounts each girl should pay	1x4 = 4 u	1x4 = 4 u	1x4 = 4 u	1x4 = 4 u	4x4 = 16 u

(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same.  LCM of 4 and 16 is 16.

Extra amount that Hazel paid 
= 5 u - 4 u
= 1 u

1 u = 17

Total amount that Abi and Zara paid at first
= 11 u
= 11 x 17
= $187

1 p + 1 p + 15 = 187
2 p = 187 - 15
2 p = 172

1 p = 172 ÷ 2 = 86

Amount that Marion needed to pay Abi
= 1 p - 4 u
= 86 - 4 x 17
= 86 - 68
= $18

(b)
Amount that Marion needed to pay Zara
= (1 p + 15) - 4 u
= (86 + 15) - 4 x 17
= 101 - 68
= $33

Answer(s): (a) $18; (b) $33