Kimberly, Lynn, Gillian and Jean went to buy a gift for their grandfather. They shared the cost equally among themselves. However, Jean forgot to bring her money. So, the other 3 girls paid for the gift first. Gillian paid
79 of the amount Kimberly and Lynn paid. Lynn paid $3 more than Kimberly. The next day, Jean returned $15 to Gillian and some money to Kimberly and Lynn. How much did Jean return to
- Kimberly?
- Lynn?
|
Kimberly |
Lynn |
Gillian |
Jean |
Total |
Comparing the amounts 3 girls paid first |
9 u
|
7 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 3
|
|
|
|
Amounts that each girl paid for Jean first |
- ? |
- ? |
- 15
|
+ 15 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Gillian paid
= 7 u - 4 u
= 3 u
3 u = 15
1 u = 15 ÷ 3 = 5
Total amount that Kimberly and Lynn paid at first
= 9 u
= 9 x 5
= $45
1 p + 1 p + 3 = 45
2 p = 45 - 3
2 p = 42
1 p = 42 ÷ 2 = 21
Amount that Jean needed to pay Kimberly
= 1 p - 4 u
= 21 - 4 x 5
= 21 - 20
= $1
(b)
Amount that Jean needed to pay Lynn
= (1 p + 3) - 4 u
= (21 + 3) - 4 x 5
= 24 - 20
= $4
Answer(s): (a) $1; (b) $4