Xylia, Emma, Hilda and Hazel went to buy a souvenir for their auntie. They shared the cost equally among themselves. However, Hazel forgot to bring her money. So, the other 3 girls paid for the souvenir first. Hilda paid
79 of the amount Xylia and Emma paid. Emma paid $7 more than Xylia. The next day, Hazel returned $27 to Hilda and some money to Xylia and Emma. How much did Hazel return to
- Xylia?
- Emma?
|
Xylia |
Emma |
Hilda |
Hazel |
Total |
Comparing the amounts 3 girls paid first |
9 u
|
7 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 7
|
|
|
|
Amounts that each girl paid for Hazel first |
- ? |
- ? |
- 27
|
+ 27 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Hilda paid
= 7 u - 4 u
= 3 u
3 u = 27
1 u = 27 ÷ 3 = 9
Total amount that Xylia and Emma paid at first
= 9 u
= 9 x 9
= $81
1 p + 1 p + 7 = 81
2 p = 81 - 7
2 p = 74
1 p = 74 ÷ 2 = 37
Amount that Hazel needed to pay Xylia
= 1 p - 4 u
= 37 - 4 x 9
= 37 - 36
= $1
(b)
Amount that Hazel needed to pay Emma
= (1 p + 7) - 4 u
= (37 + 7) - 4 x 9
= 44 - 36
= $8
Answer(s): (a) $1; (b) $8