Dana, Tina, Roshel and Lynn went to buy a present for their father. They shared the cost equally among themselves. However, Lynn forgot to bring her money. So, the other 3 girls paid for the present first. Roshel paid ⁷₉ of the amount Dana and Tina paid. Tina paid $2 more than Dana. The next day, Lynn returned $30 to Roshel and some money to Dana and Tina. How much did Lynn return to

1. Dana?
2. Tina?

	Dana	Tina	Roshel	Lynn	Total
Comparing the amounts 3 girls paid first	9 u		7 u		16 u
Comparing the amounts 2 girls paid first	1 p	1 p + 2
Amounts that each girl paid for Lynn first	- ?	- ?	- 30	+ 30 + ?
Comparing the amounts each girl should pay	1x4 = 4 u	1x4 = 4 u	1x4 = 4 u	1x4 = 4 u	4x4 = 16 u

(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same.  LCM of 4 and 16 is 16.

Extra amount that Roshel paid 
= 7 u - 4 u
= 3 u

3 u = 30

1 u = 30 ÷ 3 = 10

Total amount that Dana and Tina paid at first
= 9 u
= 9 x 10
= $90

1 p + 1 p + 2 = 90
2 p = 90 - 2
2 p = 88

1 p = 88 ÷ 2 = 44

Amount that Lynn needed to pay Dana
= 1 p - 4 u
= 44 - 4 x 10
= 44 - 40
= $4

(b)
Amount that Lynn needed to pay Tina
= (1 p + 2) - 4 u
= (44 + 2) - 4 x 10
= 46 - 40
= $6

Answer(s): (a) $4; (b) $6