Tina, Natalie, Anna and Nora went to buy a gift for their younger brother. They shared the cost equally among themselves. However, Nora forgot to bring her money. So, the other 3 girls paid for the gift first. Anna paid
79 of the amount Tina and Natalie paid. Natalie paid $8 more than Tina. The next day, Nora returned $36 to Anna and some money to Tina and Natalie. How much did Nora return to
- Tina?
- Natalie?
|
Tina |
Natalie |
Anna |
Nora |
Total |
Comparing the amounts 3 girls paid first |
9 u
|
7 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 8
|
|
|
|
Amounts that each girl paid for Nora first |
- ? |
- ? |
- 36
|
+ 36 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Anna paid
= 7 u - 4 u
= 3 u
3 u = 36
1 u = 36 ÷ 3 = 12
Total amount that Tina and Natalie paid at first
= 9 u
= 9 x 12
= $108
1 p + 1 p + 8 = 108
2 p = 108 - 8
2 p = 100
1 p = 100 ÷ 2 = 50
Amount that Nora needed to pay Tina
= 1 p - 4 u
= 50 - 4 x 12
= 50 - 48
= $2
(b)
Amount that Nora needed to pay Natalie
= (1 p + 8) - 4 u
= (50 + 8) - 4 x 12
= 58 - 48
= $10
Answer(s): (a) $2; (b) $10