Diana, Joelle, Abi and Jade went to buy a souvenir for their auntie. They shared the cost equally among themselves. However, Jade forgot to bring her money. So, the other 3 girls paid for the souvenir first. Abi paid ⁷₉ of the amount Diana and Joelle paid. Joelle paid $10 more than Diana. The next day, Jade returned $36 to Abi and some money to Diana and Joelle. How much did Jade return to

1. Diana?
2. Joelle?

	Diana	Joelle	Abi	Jade	Total
Comparing the amounts 3 girls paid first	9 u		7 u		16 u
Comparing the amounts 2 girls paid first	1 p	1 p + 10
Amounts that each girl paid for Jade first	- ?	- ?	- 36	+ 36 + ?
Comparing the amounts each girl should pay	1x4 = 4 u	1x4 = 4 u	1x4 = 4 u	1x4 = 4 u	4x4 = 16 u

(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same.  LCM of 4 and 16 is 16.

Extra amount that Abi paid 
= 7 u - 4 u
= 3 u

3 u = 36

1 u = 36 ÷ 3 = 12

Total amount that Diana and Joelle paid at first
= 9 u
= 9 x 12
= $108

1 p + 1 p + 10 = 108
2 p = 108 - 10
2 p = 98

1 p = 98 ÷ 2 = 49

Amount that Jade needed to pay Diana
= 1 p - 4 u
= 49 - 4 x 12
= 49 - 48
= $1

(b)
Amount that Jade needed to pay Joelle
= (1 p + 10) - 4 u
= (49 + 10) - 4 x 12
= 59 - 48
= $11

Answer(s): (a) $1; (b) $11