Jade, Esther, Marion and Tiffany went to buy a gift for their younger brother. They shared the cost equally among themselves. However, Tiffany forgot to bring her money. So, the other 3 girls paid for the gift first. Marion paid
79 of the amount Jade and Esther paid. Esther paid $3 more than Jade. The next day, Tiffany returned $21 to Marion and some money to Jade and Esther. How much did Tiffany return to
- Jade?
- Esther?
|
Jade |
Esther |
Marion |
Tiffany |
Total |
Comparing the amounts 3 girls paid first |
9 u
|
7 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 3
|
|
|
|
Amounts that each girl paid for Tiffany first |
- ? |
- ? |
- 21
|
+ 21 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Marion paid
= 7 u - 4 u
= 3 u
3 u = 21
1 u = 21 ÷ 3 = 7
Total amount that Jade and Esther paid at first
= 9 u
= 9 x 7
= $63
1 p + 1 p + 3 = 63
2 p = 63 - 3
2 p = 60
1 p = 60 ÷ 2 = 30
Amount that Tiffany needed to pay Jade
= 1 p - 4 u
= 30 - 4 x 7
= 30 - 28
= $2
(b)
Amount that Tiffany needed to pay Esther
= (1 p + 3) - 4 u
= (30 + 3) - 4 x 7
= 33 - 28
= $5
Answer(s): (a) $2; (b) $5