Xylia, Jade, Tammy and Fiona went to buy a gift for their older brother. They shared the cost equally among themselves. However, Fiona forgot to bring her money. So, the other 3 girls paid for the gift first. Tammy paid
511 of the amount Xylia and Jade paid. Jade paid $8 more than Xylia. The next day, Fiona returned $10 to Tammy and some money to Xylia and Jade. How much did Fiona return to
- Xylia?
- Jade?
|
Xylia |
Jade |
Tammy |
Fiona |
Total |
Comparing the amounts 3 girls paid first |
11 u
|
5 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 8
|
|
|
|
Amounts that each girl paid for Fiona first |
- ? |
- ? |
- 10
|
+ 10 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Tammy paid
= 5 u - 4 u
= 1 u
1 u = 10
Total amount that Xylia and Jade paid at first
= 11 u
= 11 x 10
= $110
1 p + 1 p + 8 = 110
2 p = 110 - 8
2 p = 102
1 p = 102 ÷ 2 = 51
Amount that Fiona needed to pay Xylia
= 1 p - 4 u
= 51 - 4 x 10
= 51 - 40
= $11
(b)
Amount that Fiona needed to pay Jade
= (1 p + 8) - 4 u
= (51 + 8) - 4 x 10
= 59 - 40
= $19
Answer(s): (a) $11; (b) $19