Yen, Winnie, Natalie and Marion went to buy a gift for their younger sister. They shared the cost equally among themselves. However, Marion forgot to bring her money. So, the other 3 girls paid for the gift first. Natalie paid
511 of the amount Yen and Winnie paid. Winnie paid $17 more than Yen. The next day, Marion returned $7 to Natalie and some money to Yen and Winnie. How much did Marion return to
- Yen?
- Winnie?
|
Yen |
Winnie |
Natalie |
Marion |
Total |
Comparing the amounts 3 girls paid first |
11 u
|
5 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 17
|
|
|
|
Amounts that each girl paid for Marion first |
- ? |
- ? |
- 7
|
+ 7 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Natalie paid
= 5 u - 4 u
= 1 u
1 u = 7
Total amount that Yen and Winnie paid at first
= 11 u
= 11 x 7
= $77
1 p + 1 p + 17 = 77
2 p = 77 - 17
2 p = 60
1 p = 60 ÷ 2 = 30
Amount that Marion needed to pay Yen
= 1 p - 4 u
= 30 - 4 x 7
= 30 - 28
= $2
(b)
Amount that Marion needed to pay Winnie
= (1 p + 17) - 4 u
= (30 + 17) - 4 x 7
= 47 - 28
= $19
Answer(s): (a) $2; (b) $19