Victoria, Cathy, Jean and Tina went to buy a present for their father. They shared the cost equally among themselves. However, Tina forgot to bring her money. So, the other 3 girls paid for the present first. Jean paid
79 of the amount Victoria and Cathy paid. Cathy paid $7 more than Victoria. The next day, Tina returned $33 to Jean and some money to Victoria and Cathy. How much did Tina return to
- Victoria?
- Cathy?
|
Victoria |
Cathy |
Jean |
Tina |
Total |
Comparing the amounts 3 girls paid first |
9 u
|
7 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 7
|
|
|
|
Amounts that each girl paid for Tina first |
- ? |
- ? |
- 33
|
+ 33 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Jean paid
= 7 u - 4 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
Total amount that Victoria and Cathy paid at first
= 9 u
= 9 x 11
= $99
1 p + 1 p + 7 = 99
2 p = 99 - 7
2 p = 92
1 p = 92 ÷ 2 = 46
Amount that Tina needed to pay Victoria
= 1 p - 4 u
= 46 - 4 x 11
= 46 - 44
= $2
(b)
Amount that Tina needed to pay Cathy
= (1 p + 7) - 4 u
= (46 + 7) - 4 x 11
= 53 - 44
= $9
Answer(s): (a) $2; (b) $9