Shiyun, Sarah, Esther and Opal went to buy a souvenir for their older sister. They shared the cost equally among themselves. However, Opal forgot to bring her money. So, the other 3 girls paid for the souvenir first. Esther paid
511 of the amount Shiyun and Sarah paid. Sarah paid $20 more than Shiyun. The next day, Opal returned $18 to Esther and some money to Shiyun and Sarah. How much did Opal return to
- Shiyun?
- Sarah?
|
Shiyun |
Sarah |
Esther |
Opal |
Total |
Comparing the amounts 3 girls paid first |
11 u
|
5 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 20
|
|
|
|
Amounts that each girl paid for Opal first |
- ? |
- ? |
- 18
|
+ 18 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Esther paid
= 5 u - 4 u
= 1 u
1 u = 18
Total amount that Shiyun and Sarah paid at first
= 11 u
= 11 x 18
= $198
1 p + 1 p + 20 = 198
2 p = 198 - 20
2 p = 178
1 p = 178 ÷ 2 = 89
Amount that Opal needed to pay Shiyun
= 1 p - 4 u
= 89 - 4 x 18
= 89 - 72
= $17
(b)
Amount that Opal needed to pay Sarah
= (1 p + 20) - 4 u
= (89 + 20) - 4 x 18
= 109 - 72
= $37
Answer(s): (a) $17; (b) $37