Tammy, Barbara, Tiffany and Diana went to buy a gift for their younger sister. They shared the cost equally among themselves. However, Diana forgot to bring her money. So, the other 3 girls paid for the gift first. Tiffany paid
511 of the amount Tammy and Barbara paid. Barbara paid $5 more than Tammy. The next day, Diana returned $11 to Tiffany and some money to Tammy and Barbara. How much did Diana return to
- Tammy?
- Barbara?
|
Tammy |
Barbara |
Tiffany |
Diana |
Total |
Comparing the amounts 3 girls paid first |
11 u
|
5 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 5
|
|
|
|
Amounts that each girl paid for Diana first |
- ? |
- ? |
- 11
|
+ 11 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Tiffany paid
= 5 u - 4 u
= 1 u
1 u = 11
Total amount that Tammy and Barbara paid at first
= 11 u
= 11 x 11
= $121
1 p + 1 p + 5 = 121
2 p = 121 - 5
2 p = 116
1 p = 116 ÷ 2 = 58
Amount that Diana needed to pay Tammy
= 1 p - 4 u
= 58 - 4 x 11
= 58 - 44
= $14
(b)
Amount that Diana needed to pay Barbara
= (1 p + 5) - 4 u
= (58 + 5) - 4 x 11
= 63 - 44
= $19
Answer(s): (a) $14; (b) $19