Raeann, Nicole, Abi and Tina went to buy a souvenir for their older sister. They shared the cost equally among themselves. However, Tina forgot to bring her money. So, the other 3 girls paid for the souvenir first. Abi paid ⁷₉ of the amount Raeann and Nicole paid. Nicole paid $5 more than Raeann. The next day, Tina returned $27 to Abi and some money to Raeann and Nicole. How much did Tina return to

1. Raeann?
2. Nicole?

	Raeann	Nicole	Abi	Tina	Total
Comparing the amounts 3 girls paid first	9 u		7 u		16 u
Comparing the amounts 2 girls paid first	1 p	1 p + 5
Amounts that each girl paid for Tina first	- ?	- ?	- 27	+ 27 + ?
Comparing the amounts each girl should pay	1x4 = 4 u	1x4 = 4 u	1x4 = 4 u	1x4 = 4 u	4x4 = 16 u

(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same.  LCM of 4 and 16 is 16.

Extra amount that Abi paid 
= 7 u - 4 u
= 3 u

3 u = 27

1 u = 27 ÷ 3 = 9

Total amount that Raeann and Nicole paid at first
= 9 u
= 9 x 9
= $81

1 p + 1 p + 5 = 81
2 p = 81 - 5
2 p = 76

1 p = 76 ÷ 2 = 38

Amount that Tina needed to pay Raeann
= 1 p - 4 u
= 38 - 4 x 9
= 38 - 36
= $2

(b)
Amount that Tina needed to pay Nicole
= (1 p + 5) - 4 u
= (38 + 5) - 4 x 9
= 43 - 36
= $7

Answer(s): (a) $2; (b) $7