Elyse, Vanessa, Jean and Kylie went to buy a present for their father. They shared the cost equally among themselves. However, Kylie forgot to bring her money. So, the other 3 girls paid for the present first. Jean paid
79 of the amount Elyse and Vanessa paid. Vanessa paid $3 more than Elyse. The next day, Kylie returned $33 to Jean and some money to Elyse and Vanessa. How much did Kylie return to
- Elyse?
- Vanessa?
|
Elyse |
Vanessa |
Jean |
Kylie |
Total |
Comparing the amounts 3 girls paid first |
9 u
|
7 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 3
|
|
|
|
Amounts that each girl paid for Kylie first |
- ? |
- ? |
- 33
|
+ 33 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Jean paid
= 7 u - 4 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
Total amount that Elyse and Vanessa paid at first
= 9 u
= 9 x 11
= $99
1 p + 1 p + 3 = 99
2 p = 99 - 3
2 p = 96
1 p = 96 ÷ 2 = 48
Amount that Kylie needed to pay Elyse
= 1 p - 4 u
= 48 - 4 x 11
= 48 - 44
= $4
(b)
Amount that Kylie needed to pay Vanessa
= (1 p + 3) - 4 u
= (48 + 3) - 4 x 11
= 51 - 44
= $7
Answer(s): (a) $4; (b) $7