Fanny, Marion, Lynn and Joelle went to buy a present for their younger brother. They shared the cost equally among themselves. However, Joelle forgot to bring her money. So, the other 3 girls paid for the present first. Lynn paid
511 of the amount Fanny and Marion paid. Marion paid $4 more than Fanny. The next day, Joelle returned $10 to Lynn and some money to Fanny and Marion. How much did Joelle return to
- Fanny?
- Marion?
|
Fanny |
Marion |
Lynn |
Joelle |
Total |
Comparing the amounts 3 girls paid first |
11 u
|
5 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 4
|
|
|
|
Amounts that each girl paid for Joelle first |
- ? |
- ? |
- 10
|
+ 10 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Lynn paid
= 5 u - 4 u
= 1 u
1 u = 10
Total amount that Fanny and Marion paid at first
= 11 u
= 11 x 10
= $110
1 p + 1 p + 4 = 110
2 p = 110 - 4
2 p = 106
1 p = 106 ÷ 2 = 53
Amount that Joelle needed to pay Fanny
= 1 p - 4 u
= 53 - 4 x 10
= 53 - 40
= $13
(b)
Amount that Joelle needed to pay Marion
= (1 p + 4) - 4 u
= (53 + 4) - 4 x 10
= 57 - 40
= $17
Answer(s): (a) $13; (b) $17