Dana, Wendy, Betty and Kimberly went to buy a souvenir for their auntie. They shared the cost equally among themselves. However, Kimberly forgot to bring her money. So, the other 3 girls paid for the souvenir first. Betty paid
511 of the amount Dana and Wendy paid. Wendy paid $5 more than Dana. The next day, Kimberly returned $15 to Betty and some money to Dana and Wendy. How much did Kimberly return to
- Dana?
- Wendy?
|
Dana |
Wendy |
Betty |
Kimberly |
Total |
Comparing the amounts 3 girls paid first |
11 u
|
5 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 5
|
|
|
|
Amounts that each girl paid for Kimberly first |
- ? |
- ? |
- 15
|
+ 15 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Betty paid
= 5 u - 4 u
= 1 u
1 u = 15
Total amount that Dana and Wendy paid at first
= 11 u
= 11 x 15
= $165
1 p + 1 p + 5 = 165
2 p = 165 - 5
2 p = 160
1 p = 160 ÷ 2 = 80
Amount that Kimberly needed to pay Dana
= 1 p - 4 u
= 80 - 4 x 15
= 80 - 60
= $20
(b)
Amount that Kimberly needed to pay Wendy
= (1 p + 5) - 4 u
= (80 + 5) - 4 x 15
= 85 - 60
= $25
Answer(s): (a) $20; (b) $25