Xylia, Shannon, Jane and Vanessa went to buy a present for their cousin. They shared the cost equally among themselves. However, Vanessa forgot to bring her money. So, the other 3 girls paid for the present first. Jane paid
79 of the amount Xylia and Shannon paid. Shannon paid $5 more than Xylia. The next day, Vanessa returned $33 to Jane and some money to Xylia and Shannon. How much did Vanessa return to
- Xylia?
- Shannon?
|
Xylia |
Shannon |
Jane |
Vanessa |
Total |
Comparing the amounts 3 girls paid first |
9 u
|
7 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 5
|
|
|
|
Amounts that each girl paid for Vanessa first |
- ? |
- ? |
- 33
|
+ 33 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Jane paid
= 7 u - 4 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
Total amount that Xylia and Shannon paid at first
= 9 u
= 9 x 11
= $99
1 p + 1 p + 5 = 99
2 p = 99 - 5
2 p = 94
1 p = 94 ÷ 2 = 47
Amount that Vanessa needed to pay Xylia
= 1 p - 4 u
= 47 - 4 x 11
= 47 - 44
= $3
(b)
Amount that Vanessa needed to pay Shannon
= (1 p + 5) - 4 u
= (47 + 5) - 4 x 11
= 52 - 44
= $8
Answer(s): (a) $3; (b) $8