Fanny, Tiffany, Penelope and Kimberly went to buy a gift for their older brother. They shared the cost equally among themselves. However, Kimberly forgot to bring her money. So, the other 3 girls paid for the gift first. Penelope paid
79 of the amount Fanny and Tiffany paid. Tiffany paid $2 more than Fanny. The next day, Kimberly returned $36 to Penelope and some money to Fanny and Tiffany. How much did Kimberly return to
- Fanny?
- Tiffany?
|
Fanny |
Tiffany |
Penelope |
Kimberly |
Total |
Comparing the amounts 3 girls paid first |
9 u
|
7 u
|
|
16 u
|
Comparing the amounts 2 girls paid first |
1 p
|
1 p + 2
|
|
|
|
Amounts that each girl paid for Kimberly first |
- ? |
- ? |
- 36
|
+ 36 + ? |
|
Comparing the amounts each girl should pay |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
1x4 = 4 u |
4x4 = 16 u |
(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same. LCM of 4 and 16 is 16.
Extra amount that Penelope paid
= 7 u - 4 u
= 3 u
3 u = 36
1 u = 36 ÷ 3 = 12
Total amount that Fanny and Tiffany paid at first
= 9 u
= 9 x 12
= $108
1 p + 1 p + 2 = 108
2 p = 108 - 2
2 p = 106
1 p = 106 ÷ 2 = 53
Amount that Kimberly needed to pay Fanny
= 1 p - 4 u
= 53 - 4 x 12
= 53 - 48
= $5
(b)
Amount that Kimberly needed to pay Tiffany
= (1 p + 2) - 4 u
= (53 + 2) - 4 x 12
= 55 - 48
= $7
Answer(s): (a) $5; (b) $7