Hazel, Penelope, Tammy and Min went to buy a gift for their younger sister. They shared the cost equally among themselves. However, Min forgot to bring her money. So, the other 3 girls paid for the gift first. Tammy paid ⁷₉ of the amount Hazel and Penelope paid. Penelope paid $7 more than Hazel. The next day, Min returned $33 to Tammy and some money to Hazel and Penelope. How much did Min return to

1. Hazel?
2. Penelope?

	Hazel	Penelope	Tammy	Min	Total
Comparing the amounts 3 girls paid first	9 u		7 u		16 u
Comparing the amounts 2 girls paid first	1 p	1 p + 7
Amounts that each girl paid for Min first	- ?	- ?	- 33	+ 33 + ?
Comparing the amounts each girl should pay	1x4 = 4 u	1x4 = 4 u	1x4 = 4 u	1x4 = 4 u	4x4 = 16 u

(a)
The total amount that the 4 girls paid is repeated. Make the total amount the same.  LCM of 4 and 16 is 16.

Extra amount that Tammy paid 
= 7 u - 4 u
= 3 u

3 u = 33

1 u = 33 ÷ 3 = 11

Total amount that Hazel and Penelope paid at first
= 9 u
= 9 x 11
= $99

1 p + 1 p + 7 = 99
2 p = 99 - 7
2 p = 92

1 p = 92 ÷ 2 = 46

Amount that Min needed to pay Hazel
= 1 p - 4 u
= 46 - 4 x 11
= 46 - 44
= $2

(b)
Amount that Min needed to pay Penelope
= (1 p + 7) - 4 u
= (46 + 7) - 4 x 11
= 53 - 44
= $9

Answer(s): (a) $2; (b) $9