A total of 99 black staplers and silver staplers are in a container. The ratio of black staplers to silver staplers was 1 : 2. Some yellow staplers and blue staplers were put into the container. For every 3 silver staplers that were already in the container, 7 blue ones were added. Then, the final number of black staplers and yellow staplers was
12 the final number of silver staplers and blue staplers. Find the total number of yellow and blue staplers.
| Yellow staplers |
Black staplers |
Silver staplers |
Blue staplers |
| |
1x3 |
2x3 |
|
| |
|
3x2 |
7x2 |
| 1x10 |
2x10 |
| 7 u |
3 u |
6 u |
14 u |
The number of silver staplers is repeated. Make the number of silver staplers the same. LCM of 2 and 3 is 6.
The total number of silver staplers and blue staplers is repeated. Make the total number of silver and blue staplers the same. LCM of 20 and 2 is 20.
Total number of black staplers and silver staplers
= 3 u + 6 u
= 9 u
9 u = 99
1 u = 99 ÷ 9 = 11
Total number of yellow and blue staplers
= 7 u + 14 u
= 21 u
= 21 x 11
= 231
Answer(s): 231
