A total of 32 brown markers and white markers are in a container. The ratio of brown markers to white markers was 1 : 3. Some yellow markers and black markers were put into the container. For every 2 white markers that were already in the container, 4 black ones were added. Then, the final number of brown markers and yellow markers was ²₃ the final number of white markers and black markers. Find the total number of yellow and black markers.

Yellow markers	Brown markers	White markers	Black markers
	1x2	3x2
		2x3	4x3
2x6		3x6
10 u	2 u	6 u	12 u

The number of white markers is repeated.  Make the number of white markers the same.  LCM of 3 and 2 is 6.

The total number of white markers and black markers is repeated.  Make the total number of white and black markers the same.  LCM of 18 and 3 is 18.

Total number of brown markers and white markers
= 2 u + 6 u
= 8 u

8 u = 32

1 u = 32 ÷ 8 = 4

Total number of yellow and black markers
= 10 u + 12 u
= 22 u
= 22 x 4
= 88

Answer(s): 88