A total of 16 yellow markers and red markers are in a container. The ratio of yellow markers to red markers was 1 : 3. Some white markers and blue markers were put into the container. For every 2 red markers that were already in the container, 14 blue ones were added. Then, the final number of yellow markers and white markers was ³₈ the final number of red markers and blue markers. Find the total number of white and blue markers.

White markers	Yellow markers	Red markers	Blue markers
	1x2	3x2
		2x3	14x3
3x6		8x6
16 u	2 u	6 u	42 u

The number of red markers is repeated.  Make the number of red markers the same.  LCM of 3 and 2 is 6.

The total number of red markers and blue markers is repeated.  Make the total number of red and blue markers the same.  LCM of 48 and 8 is 48.

Total number of yellow markers and red markers
= 2 u + 6 u
= 8 u

8 u = 16

1 u = 16 ÷ 8 = 2

Total number of white and blue markers
= 16 u + 42 u
= 58 u
= 58 x 2
= 116

Answer(s): 116