A total of 80 green markers and red markers are in a container. The ratio of green markers to red markers was 1 : 3. Some yellow markers and brown markers were put into the container. For every 4 red markers that were already in the container, 6 brown ones were added. Then, the final number of green markers and yellow markers was ¹₃ the final number of red markers and brown markers. Find the total number of yellow and brown markers.

Yellow markers	Green markers	Red markers	Brown markers
	1x4	3x4
		4x3	6x3
1x10		3x10
6 u	4 u	12 u	18 u

The number of red markers is repeated.  Make the number of red markers the same.  LCM of 3 and 4 is 12.

The total number of red markers and brown markers is repeated.  Make the total number of red and brown markers the same.  LCM of 30 and 3 is 30.

Total number of green markers and red markers
= 4 u + 12 u
= 16 u

16 u = 80

1 u = 80 ÷ 16 = 5

Total number of yellow and brown markers
= 6 u + 18 u
= 24 u
= 24 x 5
= 120

Answer(s): 120