A total of 63 yellow pencils and black pencils are in a container. The ratio of yellow pencils to black pencils was 1 : 2. Some green pencils and red pencils were put into the container. For every 6 black pencils that were already in the container, 4 red ones were added. Then, the final number of yellow pencils and green pencils was
45 the final number of black pencils and red pencils. Find the total number of green and red pencils.
Green pencils |
Yellow pencils |
Black pencils |
Red pencils |
|
1x3 |
2x3 |
|
|
|
6x1 |
4x1 |
4x2 |
5x2 |
5 u |
3 u |
6 u |
4 u |
The number of black pencils is repeated. Make the number of black pencils the same. LCM of 2 and 6 is 6.
The total number of black pencils and red pencils is repeated. Make the total number of black and red pencils the same. LCM of 10 and 5 is 10.
Total number of yellow pencils and black pencils
= 3 u + 6 u
= 9 u
9 u = 63
1 u = 63 ÷ 9 = 7
Total number of green and red pencils
= 5 u + 4 u
= 9 u
= 9 x 7
= 63
Answer(s): 63