A total of 33 brown pens and gold pens are in a container. The ratio of brown pens to gold pens was 3 : 8. Some blue pens and silver pens were put into the container. For every 4 gold pens that were already in the container, 6 silver ones were added. Then, the final number of brown pens and blue pens was
12 the final number of gold pens and silver pens. Find the total number of blue and silver pens.
| Blue pens |
Brown pens |
Gold pens |
Silver pens |
| |
3x1 |
8x1 |
|
| |
|
4x2 |
6x2 |
| 1x10 |
2x10 |
| 7 u |
3 u |
8 u |
12 u |
The number of gold pens is repeated. Make the number of gold pens the same. LCM of 8 and 4 is 8.
The total number of gold pens and silver pens is repeated. Make the total number of gold and silver pens the same. LCM of 20 and 2 is 20.
Total number of brown pens and gold pens
= 3 u + 8 u
= 11 u
11 u = 33
1 u = 33 ÷ 11 = 3
Total number of blue and silver pens
= 7 u + 12 u
= 19 u
= 19 x 3
= 57
Answer(s): 57
