A total of 126 purple markers and silver markers are in a container. The ratio of purple markers to silver markers was 2 : 5. Some blue markers and gold markers were put into the container. For every 3 silver markers that were already in the container, 2 gold ones were added. Then, the final number of purple markers and blue markers was
45 the final number of silver markers and gold markers. Find the total number of blue and gold markers.
Blue markers |
Purple markers |
Silver markers |
Gold markers |
|
2x3 |
5x3 |
|
|
|
3x5 |
2x5 |
4x5 |
5x5 |
14 u |
6 u |
15 u |
10 u |
The number of silver markers is repeated. Make the number of silver markers the same. LCM of 5 and 3 is 15.
The total number of silver markers and gold markers is repeated. Make the total number of silver and gold markers the same. LCM of 25 and 5 is 25.
Total number of purple markers and silver markers
= 6 u + 15 u
= 21 u
21 u = 126
1 u = 126 ÷ 21 = 6
Total number of blue and gold markers
= 14 u + 10 u
= 24 u
= 24 x 6
= 144
Answer(s): 144