A total of 60 red pens and purple pens are in a container. The ratio of red pens to purple pens was 1 : 2. Some gold pens and blue pens were put into the container. For every 4 purple pens that were already in the container, 14 blue ones were added. Then, the final number of red pens and gold pens was
23 the final number of purple pens and blue pens. Find the total number of gold and blue pens.
Gold pens |
Red pens |
Purple pens |
Blue pens |
|
1x2 |
2x2 |
|
|
|
4x1 |
14x1 |
2x6 |
3x6 |
10 u |
2 u |
4 u |
14 u |
The number of purple pens is repeated. Make the number of purple pens the same. LCM of 2 and 4 is 4.
The total number of purple pens and blue pens is repeated. Make the total number of purple and blue pens the same. LCM of 18 and 3 is 18.
Total number of red pens and purple pens
= 2 u + 4 u
= 6 u
6 u = 60
1 u = 60 ÷ 6 = 10
Total number of gold and blue pens
= 10 u + 14 u
= 24 u
= 24 x 10
= 240
Answer(s): 240