There are some students in the fun fair.
110 of them are boys, of whom 80% of them do not wear hats.
59 of the girls do not wear hats. What is the percentage of the students in the fun fair who wear hats?
| Boys |
Girls |
Total |
1x5 =
5 u |
9x5 =
45 u |
10x5 =
50 u |
| No hats |
Hats |
No hats |
Hats |
|
| 4x1 |
1x1 |
5x5 |
4x5 |
|
| 4 u |
1 u |
25 u |
20 u |
50 u |
80% =
80100=
45 The number of boys is the repeated identity. Make the number of boys the same. LCM of 1 and 5 is 5.
Number of students who wear hats
= 1 u + 20 u
= 21 u
Total number of students
= 4 u + 1 u + 25 u + 20 u
= 50 u
Percentage of the students in the fun fair who wear hats
=
2150 x 100%
= 42%
Answer(s): 42%
