In a school, 0.9 of the girls and 0.3 of the boys take part in interviews. There is an equal number of boys and girls who do not take part in interviews. If 726 children take part in interviews, how many less children do not take part in interviews than those who take part in interviews?
Girls |
Boys |
Take part |
Do not take part |
Take part |
Do not take part |
9x7 |
1x7 |
3 |
7 |
|
1x7 |
|
1x7 |
63 u |
7 u |
3 u |
7 u |
0.9 =
910 Girls that take part : Girls that do not take part = 9 : 1
0.3 =
310 Boys that take part : Boys that do not take part = 3 : 7
The number of boys who do not take part is repeated. Make the number of boys who do not take part the same. LCM of 1 and 7 is 7.
Number of children who take part in interviews
= 63 u + 3 u
= 66 u
66 u = 726
1 u = 726 ÷ 66 = 11
Number of children who do not take part in interviews
= 7 u + 7 u
= 14 u
Number of less children who do not take part in interviews than those who take part in interviews
= 66 u - 14 u
= 52 u
= 52 x 11
= 572
Answer(s): 572