In a school, 0.5 of the girls and 0.7 of the boys take part in interviews. There is an equal number of boys and girls who do not take part in interviews. If 114 students do not take part in interviews, how many more students take part in interviews than those who do not take part in interviews?
Girls |
Boys |
Take part |
Do not take part |
Take part |
Do not take part |
1x3 |
1x3 |
7 |
3 |
|
1x3 |
|
1x3 |
3 u |
3 u |
7 u |
3 u |
0.5 =
12 Girls that take part : Girls that do not take part = 1 : 1
0.7 =
710 Boys that take part : Boys that do not take part = 7 : 3
The number of boys who do not take part is repeated. Make the number of boys who do not take part the same. LCM of 1 and 3 is 3.
Number of students who do not take part in interviews
= 3 u + 3 u
= 6 u
6 u = 114
1 u = 114 ÷ 6 = 19
Number of students who take part in interviews
= 3 u + 7 u
= 10 u
Number of more students who take part in interviews than those who do not take part in interviews
= 10 u - 6 u
= 4 u
= 4 x 19
= 76
Answer(s): 76